You know vertical Angles SRU and TRV are congruent.
You are given that Sides UR and VR are congruent.
You are given that Angles SUT and SVT are congruent.
An appropriate choice is the ASA postulate, since you have congruent angles with congruent sides in between.
The area of the original polygon is:
A = 225 m ^ 2
The similar polygon area is:
A '= (k ^ 2) * (A)
Substituting values:
3 * 225 = (k ^ 2) * (225)
Clearing k we have:
k ^ 2 = 3
k = (3) ^ (1/3)
Answer:
The length of each side increased by:
k = (3) ^ (1/3)
Answer:
c and d
Step-by-step explanation:
i think
