Question

If a dart was thrown randomly at the dart board shown below, what is the probability that it would land between the outer circle and the middle circle? The radius of the bulls eye is 2 cm, the radius of the middle circle is 8 cm, and the radius of the outer circle is 14 cm
A.68%

B.67%

C.14%

D.75%

Answer 1

Answer:  B) 67%

Step-by-step explanation:

Find the Area of the Bullseye and Middle ring

A = π r²

A (inside) = π(8)² = 64π

Find the Area of the entire Target

A (target) = π (14)² = 196π

Find the Area of the Outer ring

A (outer ring) = A (target) - A(inside)

                      =   196 π    -    64π

                      =    132 π

The last step is to find the probability of landing on the outer ring:

$P=\dfrac{success (area\ of\ outer\ ring)}{total\ possible\ outcomes(area\ of\ target)}=\dfrac{132\pi}{196\pi}=0.673=\large\boxed{67\%}$