If a dart was thrown randomly at the dart board shown below, what is the probability that it would land between the outer circle
1 answer:
Answer: B) 67%
<u>Step-by-step explanation:</u>
Find the Area of the Bullseye and Middle ring
A = π r²
A (inside) = π(8)² = 64π
Find the Area of the entire Target
A (target) = π (14)² = 196π
Find the Area of the Outer ring
A (outer ring) = A (target) - A(inside)
= 196 π - 64π
= 132 π
The last step is to find the probability of landing on the outer ring:
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Answer:
The image of both graphs can be seen below:
Both functions will have the same output for an input x₀ if:
f(x₀) = g(x₀)
This means that, for that particular value of x₀, the functions will intersect each other.
So we just need to look at the graph and find the x-value where the functions intersect. (Remember that the x-values are in the horizontal axis)
We can see that it happens at x = 1.
Then the input value that produces the same output value for the two functions is:
x = 1
Answer:
0.7486 = 74.86% probability of family expenses for the weekend being more than $580.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The American Automobile Association reported that families planning to travel over the Labor Day weekend would spend an average of $735.
This means that
Assume that the amount spent is normally distributed with a standard deviation of $230.
This means that
What is the probability of family expenses for the weekend being: a. more than $580
This is 1 subtracted by the pvalue of Z when X = 580. So
has a pvalue of 0.2514
1 - 0.2514 = 0.7486
0.7486 = 74.86% probability of family expenses for the weekend being more than $580.