Answer:
k = 5
Step-by-step explanation:
y = kx
15 = k(3)
k = 15/3
k = 5
The standard form of a line is in the form

A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:

Subtract 3y from both sides:

Which of course is equivalent to

Which is the standard form, given the coefficients A=1, B=-3, C=6.
Answer:

Explanation:
05/10
Simplifying
1/2
or 2^-1
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Answer:
so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.
Step-by-step explanation:
let the fraction be x
(1/4 + 1/6)-x = 1/12
or, 10/24 - x = 1/12
or, 5/12-1/12 = x
so, x = 4/12 = 1/3
The area under the graph of the continuous uniform distribution is 1.
a. The probability that the value will be between 5 and 7 is the area between 5 and 7.

b. The probability that the value will be between 2 and 3 is the are between 2 and 3.
c. The mean is given by:

d. The variance is given by:

The standard deviation is: