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3 years ago

Please look please asap

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

7 0

This may be 3 or it also may be 3

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-2/3f=9.2 -1/8n = -2/7 12/20n = -36/44 -64.5g = -25.8 -15/28 = -9/10

user100 [1]

Step-by-step explanation:

-2/3f =9.2

cross multiply

27,6= -2f

divide both sides by 2

f = - 13.8

-1/8n = -2/7

cross multiply

-16 = -7n

divide

n = 2.29

12/20n = -36/44

cross multiply

528 = - 720n

divide

n= -0.733

-64.5g = -25.8

divide both sides by -64.5

g = -0.4

the last one has no variable

5 0

3 years ago

A useful rule of thumb called the "rule of 70" states that if something grows at a constant rate of z percent per year, it doubl

vesna_86 [32]

The answer is b. (70/z). If I put $100 into a savings account and the annual growth rate is 10%, the 70/10%= 7 years that the initial $100 would take to double.

4 0

3 years ago

A number is decreased by seven. Then, the new number is multiplied by 3 to get an answer of -9. What is the original number?

stellarik [79]

4-7= -3
-3x3= -9
answer is C

8 0

3 years ago

A shipment To a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 ar

riadik2000 [5.3K]

Answer:

630 MP3 players are likely to be defective.

Step-by-step explanation:

Given:

A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.

Now, to find the MP3 players which are likely to be defective.

Let the defective MP3 players be $x.$

Total MP3 players = 4500.

In sample of 50 MP3 players 7 are defective.

Now, setting the proportion:

If, 50 is equivalent to 7.

Then, 4500 is equivalent to $x.$

Now, to solve using cross multiplication method:

$\frac{50}{7} =\frac{4500}{x}$

By cross multiplying we get:

$50x=31500$

Dividing both sides by 50 we get:

$x=630.$

Therefore, 630 MP3 players are likely to be defective.

5 0

3 years ago

Solve each of the following quadratic equations 3x=0.5x^2 0=5x^2-2x+6

UNO [17]

Question 1

$3x=0.5x^{2}\\\\6x=x^{2} \\ \\ x^{2}-6x=0 \\ \\ x(x-6)=0 \\ \\ \boxed{x=0, 6}$

Question 2

$0=5x^{2}-2x+6 \\ \\ x=\frac{2 \pm \sqrt{(-2)^{2}-4(5)(6)}}{2} \\ \\ x=\frac{2 \pm \sqrt{-116}}{10} \\ \\ x=\frac{2 \pm 2i\sqrt{29}}{10} \\ \\ \boxed{x=\frac{1 \pm i\sqrt{29}}{5}}$

6 0

2 years ago