All categories

3 years ago

1. What is the slope of f(x)=3x+10

Mathematics

2 answers:

Degger [83]3 years ago

5 0

Step-by-step explanation:

Let y = f(x)

Then comparing with y = mx + c Then

y = 3x + 10

Slope (m) = 3

y - intercept (c) = 10

Now

For question 3

f(x) = 3x + 10

f(11) = 3 * 11 + 10

= 33 + 10

= 43

Hope it will help :)❤

Anna71 [15]3 years ago

3 0

1. Slope is 3
2. Y intercept is 10
3. F(11) = 43

You might be interested in

WHat is the solution of x^2 + x-6 / x-7 < 0

borishaifa [10]

Answer:

x≤-3 or 2≤x∠7

Step-by-step explanation:

It would be the first answer on the paper

5 0

3 years ago

Read 2 more answers

Math workshops and final exams: The college tutoring center staff are considering whether the center should increase the number

ludmilkaskok [199]

Answer:

2. Number of workshops attended.

Step-by-step explanation:

The variable of interest for predicting the final exam score and doing regression analysis is workshop attendance. Therefore, the response variable should be the number of workshops attended by each student.

This also agrees with what the college tutoring center staff are considering, which forms the research question: "should the center increase the number of math workshops they offer to help students improve their performance in math classes?"

3 0

4 years ago

Raelynn and Kiara are both getting their nails done today. Raelynn gets her nails done every 9 days. Kiara gets her nails done e

Leona [35]

Answer: The answer is 4 /3 .

You need to make the numbers 12 and 9 into a fraction like this 12 /9 and go to a calculator on a website that is not blocked and enter 12 /9 . the calculator on the website will show the answer of the problem . If you working this problem , the answer is 4 /3 . you need put the fraction first before will answer appears . thank you for asking for question .

4 0

3 years ago

Which of the following is equal to tan θ using coordinates on the unit circle? Question 18 options: A) x∕y B) y C) y∕x D) x

kramer

Answer:

Solution given

tan θ=opposite/adjacent=y/x is a required answer.

8 0

3 years ago

Read 2 more answers

Use a t-distribution to find a confidence interval for the difference in means μd=μ1-μ2 using the relevant sample results from p

V125BC [204]

Answer:

best estimate = Xd[bar]=4.80

margin of error = 8.66

The 99% confidence interval is -3.86 to 13.46

test statistic = -1.86

p-value = 0.0526

Decision: Reject the null hypothesis.

At the 5% significance level, you can conclude that the population mean of the difference between treatment 1 and treatment 2 is less than zero.

Step-by-step explanation:

Hello!

a) 99% CI

Using d=X₁-X₂ to determine the study variable Xd: the difference between treatment 1 and treatment 2.

Assuming that this variable has an approximately normal distribution: Xd≈N(μd;σ²d)

To calculate the sample mean and standard deviation you have to calculate the difference between the values of both treatments first.

Case 1 ; Case 2 ; Case 3 ; Case 4 ; Case 5

22-18= 4 ; 27-29= -2 ; 32-25= 7; 26-20= 6 ; 29-20= 9

n= 5

Xd[bar]= ∑X/n= 24/5= 4.80

Sd²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/4*[186-(24²)/5]= 17.7

Sd= 4.21

The parameter of interes is the population mean od the difference, μd

The best estimate for this parameter is the sample mean, Xd[bar]=4.80

Using the t-distribution, the formula for the Confidence Interval is

Xd[bar] ± $t_{n-1;1-\alpha /2}$ * $\frac{Sd}{\sqrt{n} }$

Where the margin of error is:

$t_{n-1;1-\alpha /2}$ * $\frac{Sd}{\sqrt{n} }$ = $t_{4;0.995}$ * $\frac{Sd}{\sqrt{n} }$ = 4.604* $\frac{4.21}{\sqrt{5} }$ = 8.66

99% CI [-3.86; 13.46]

b) 5% Hypothesis test

The variable of interest is defined d=X₁-X₂; Xd: the difference between treatment 1 and treatment 2. Xd≈N(μd;σ²d)

The statistic hypotheses are:

H₀: μd = 0

H₁: μd < 0

α: 0.05

The statistic to use for this test is:

$t_{H_0}= \frac{X_d[bar]-Mu_d}{\frac{Sd}{\sqrt{n} } } ~~t_{n-1}$

As before you have to calculate the difference between the observation for each case and then the sample mean and standard deviation:

Case 1 ; Case 2 ; Case 3 ; Case 4 ; Case 5 ; Case 6 ; Case 7 ; Case 8

18-18= 0; 12-19= -7; 11-25= -14; 21-21= 0; 15-19= -4; 11-14=-3; 14-15= -1; 22-20= 2

n= 8

Xd[bar]= ∑X/n= -27/8= -3.38

Sd²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[275-(-27²)/8]= 26.27

Sd= 5.13

$t_{H_0}= \frac{-3.38-0}{\frac{5.13}{\sqrt{8} } }= -1.86$

This test is one-tailed to the left, which means that you will reject the null hypothesis to small values of t, the p-value of the test has the same direction as the rejection region, this means that it is one-tailed to the left and you can calculate it as:

P(≤-1.86)= 0.0526

The decision rule using the p-value is:

If p-value > α, do not reject the null hypothesis.

If p-value ≤ α, reject the null hypothesis.

The p-value is greater than the significance level so the decision is to reject the null hypothesis.

I hope it helps!

7 0

4 years ago