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Lady_Fox [76]
3 years ago
11

Bowl A contains 6 apples and 3 mangoes this can be written as, Bowl B contain 8 apples and 2 mangoes this can be written as. Wha

t is the difference between the bowls.
Mathematics
1 answer:
Andrew [12]3 years ago
3 0

Answer:

Bowl B contains 2 apples more than Bowl A and Bowl A contains 1 mango more than Bowl B.

Step-by-step explanation:

Number of apples in Bowl A = 6

Number of mangoes in Bowl B = 8

Difference in apples = 8 - 6 = 2

So, Bowl B contains 2 apples more than Bowl A.

Number of mangoes in Bowl A = 3

Number of mangoes in Bowl B =2

Difference in mangoes = 3 - 2 = 1

So, Bowl A contains 1 mango more than Bowl B.

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A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal
GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean income = \frac{\sum X}{n} = $4.70

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = $1.83

            n = sample of parking meters = 10

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.262 < t_9 < 2.262) = 0.95  {As the critical value of t at 9 degrees of

                                            freedom are -2.262 & 2.262 with P = 2.5%}  

P(-2.262 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.262) = 0.95

P( -2.262 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu < 2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.262 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.262 \times {\frac{s}{\sqrt{n} } } , \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 4.70-2.262 \times {\frac{1.83}{\sqrt{10} } } , 4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } } ]

                                         = [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error  =  2.262 \times {\frac{s}{\sqrt{n} } }

                                          =  2.262 \times {\frac{1.83}{\sqrt{10} } }  = <u>1.31</u>

4 0
3 years ago
To break the school’s record, the girls’ time had to be faster than
Finger [1]

Answer:The answer is no they are slower by 20%

Step-by-step explanation:divide 12 by 5 then divid the answer of 12 by 5 by 2 then you get the answer of 20%

3 0
2 years ago
What is .006 as a percent
ivolga24 [154]

Answer:

.006 as a percentage is .6%

Step-by-step explanation:

Multiply your number by 100 to get the percentage.

.006 x 100 = .6

Therefore, your answer is .6%.

3 0
2 years ago
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masha68 [24]
I think it’s c or b but I’m positive it’s b
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2 years ago
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Find the length of the missing sides, round your answers to the nearest hundredth.
azamat
90 round to the nearest hundredth
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