Based on computer analysis, Microsoft labels mac addresses in the windows utilities "<u>by showing the MAC address in the 'Physical Address' field."</u>
<h3>What is MAC Address?</h3>
MAC Address is the acronym for media access control address. A distinct identifier is allocated to a network interface controller (NIC).
MAC address is used as a network address in communications within a network component.
There are two ways to check for a MAC address in the Windows Utilities which is either through Command Prompt or Network Setting.
Hence, in this case, it is concluded that the correct answer is "<u>by showing the MAC address in the 'Physical Address' field."</u>
Learn more about MAC Address here: brainly.com/question/24812654
Cognitive surplus results when leisure time and available tools allow us to engage in creative acts. It is a term that was introduced by Clay Shirky which pertains to the synthesis of the excess of people's energy, time and creativity leading to productivity sharing and creation.
Answer:
A vulnerability level of ZERO can never be obtained since all countermeasures have vulnerabilities themselves. For this reason, vulnerability can never be zero, and thus risk can never be totally eliminated.
Explanation:
also we need to be protected from scams and stuff
I am not too familiar with the Python language, but the algorithm would be something like this:
1. create a variable for the sums of the number
2. read in how many numbers the user wants to enter (let's call it N)
and then create a for loop:
for N times
read in the next number
increase the sum variable by that number
Hopefully this helps!
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
