Answer:
I think it would be 15
Step-by-step explanation:
Answer:
The number of cards Frank has is 18 and the number of cards his friend has is 24.
Step-by-step explanation:
<u><em>The correct question is </em></u>
Two friends are collecting cards. Frank has 6 more than half the number of cards as his friend. Together they have 42 cards. How many cards does each friend have?
Let
x ----> the number of cards that Frank has
y ----> the number of cards that his friend has
we know that
Together they have 42 cards
----> equation A
Frank has 6 more than half the number of cards as his friend
---> equation B
Solve the system by substitution
Substitute equation B in equation A

solve for y

<em>Find the value of x</em>

therefore
The number of cards Frank has is 18 and the number of cards his friend has is 24.
Answer:
IH < IG < HG
Step-by-step explanation:
To solve this equation remember that angle measurements correspond with sides. So, the largest angle will be opposite of the longest side and the smallest angle will be opposite of the shortest side.
First, you need to find m<I; do this by subtracting 52 and 45 from 180. This means that m<I=83, making it the largest angle. Therefore, the angles, in order of least to greatest, are <G, <H, <I. So, to find the final answer, find the sides opposite of each of the angles. This means the answer is IH < IG < HG.
Answer:
B (cylinder)
Step-by-step explanation:
Two <u>circular</u> bases which are parallel and congruent :
This basically means that the shape contains a circular base (supposedly the bottom), but since it has two bases, its on the top and the bottom. Because it's congruent, the bases are both equal in shape and size. It is also parallel as well, in which the bases have the same distance between them.
The cube doesn't have any circular bases.
The sphere doesn't have any faces, nor edges.
A cone has a circular base, but it doesn't have two.
A cylinder has two circular bases, as well as they are parallel and congruent.
So, your answer is B (cylinder).
Hope this helped !
F(2) = 3(2)^2 + 2(2) + 4
= 3(4) + 4 + 4
= 12 + 8
f(2) = 20
f(a+h) = 3(a+h)^2 + 2(a+h) + 4
= 3(a^2 + 2ah + h^2) + 2a + 2h + 4
f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4