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elena-14-01-66 [18.8K]
2 years ago
10

Simplify to create an equivalent expression. −3(2+4k)+7(2k−1)

Mathematics
2 answers:
Genrish500 [490]2 years ago
7 0

Answer:

\huge\boxed{2k-13}

Step-by-step explanation:

\sf -3(2+4k)+7(2k-1)\\Expanding \ brackets\\-6-12k+14k-7\\Combining \ like \ terms\\-12k+14k-6-7\\2k -13

prisoha [69]2 years ago
6 0
2k-13
First step= -3(2+4K)+7(2k-1)
Second step= -6 - (12k) + 14k- 7
Third step= -12k+14k - 6 -7= 2k-13
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Write equations for the horizontal and vertical lines passing through the point (4, -5).
raketka [301]

Answer:

Horizontal line: y=-5

Vertical line: x = 4

Step-by-step explanation:

As we have to determine the equations for the horizontal and vertical lines passing through the point (4, -5).

  • To determine the equation for the horizontal line passing through the point (4, -5), we must observe that the horizontal line will always have the same y-value regardless of the x-value.

Therefore, the equation of the horizontal line passing through the point (4, -5) will be: y=-5

  • To determine the equation for the vertical line passing through the point (4, -5), we must observe that the vertical line will always have the same x-value regardless of the y-value.

Therefore, the equation of the vertical line passing through the point (4, -5) will be: x=4

Hence:

Horizontal line: y=-5

Vertical line: x = 4

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2 years ago
Factor x^4 + x y^3 + x^3 + y^3 completely. Show your work.
andrey2020 [161]
\bf x^4+xy^3+x^3+y^3\impliedby \textit{now let's do some grouping}
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\stackrel{\stackrel{common}{factor}}{(x^3+y^3)}(x+1)\\\\
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\textit{now recall that }\qquad \qquad \textit{difference of cubes}
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a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
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Step-by-step explanation:

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Here is my answer. Let just give assumptions. For example,the relationship is linear.Therefore the slope, "m," is the same throughout.
Let us make patrons the independent variable, the two points are: (1314, 11333) and (1544, 13518).
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0 < profit = 9.5 patrons
0 < 9.5 patrons
0 < patron
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