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schepotkina [342]
3 years ago
5

How do I find the answer to this question?

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0
Answer:
You just did. 
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Pyramid A has a volume of 60 mm cubed and pyramid B has a volume of 937.5 mm cubed. What is the ratio of their heights?
Norma-Jean [14]
We know that
volume pyramid A=[scale factor]³*volume pyramid B
so
scale factor=∛[volume pyramid A/volume pyramid B]
scale factor=∛[60/937.5]----> scale factor=0.4

<span>the ratio of their heights is equal to the scale factor
hA/hB=0.4</span>
3 0
2 years ago
Please help me find the answer and explain the process to find the answer of the problem appreciate it :)
Natalka [10]

Answer:

Total distance traveled is 67.653 miles

Step-by-step explanation:

Side a = 14 (miles traveled South)

Side b = 25 (miles traveled East)

side c = a^{2} + b^{2}

196 + 625 = c^{2}

821 = c^{2}

\sqrt{821} = \sqrt{c^{2} }

c = 28.653 (rounded to the nearest 1000th)

Now add the three sides to get the total distance:

14 + 25 + 28.653 = 67.653

5 0
2 years ago
HELLLPPPPP PLLLLZZZZZZZ
koban [17]

I had that question yesterday

8 0
3 years ago
Solve and show work: <br> f(300) = 90 + 0.11x
Vinil7 [7]
300-90= 90-90 +0.11x                                                                                              210=0.11x                                                                                                               210/.11     0.11x/0.11
   1909 = x I think but Idk
6 0
3 years ago
State restrictions for the given equation below
Genrish500 [490]

The restriction of the given equation is cos^{2}x =cos^{2} x,  other than 0≤x≤2π.

What is restriction of equation?

Restriction of the equation is the value of domain where the value is limited.

Given,

sin^{2} xcos^{2}x +cos^4x =(1-sinx)(1+sinx)

taking cos^2x common, we get

cos^2x(sin^2x+cos^2x)=1+sinx-sinx-sin^2x

we know

sin^2x+cos^2x=1\\cos^2x=1-sin^2x

we get,

cos^2x=cos^2x

and the restriction is 0≤x≤2π.

To know more restriction, visit:

brainly.com/question/68084

#SPJ1

8 0
8 months ago
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