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kompoz [17]
2 years ago
9

Bob and Mark talk about their families. Bob says he has 3 kids, the product of their ages is 72. He gives another clue: the sum

of the ages of his children. Mark points out that there is still not enough information to accurately guess. Finally, Bob says, "My youngest child called Justice." Mark can then correctly determine the ages of Bob's children. What are the ages?
Mathematics
1 answer:
Volgvan2 years ago
7 0
I just encountered this question. Here's my answer:

Given:
3 kids
product of their ages is 72.
Youngest child.

The youngest child means that all three kids have different ages.

We need to factor 72. Let us use prime factorization.

72 ÷ 2 = 36
36 ÷ 2 = 18
18 ÷ 2 =   9
  9 ÷ 3 =   3
  3 ÷ 3 =   1

1 x 2 x 2 x 2 x 3 x 3 = 72

Based on the factors we can assume the following ages:

2 x 4 x 9   = 72
3 x 4 x 6   = 72
1 x 8 x 9   = 72  I prefer this age combination.
1 x 3 x 24 = 72
<span>1 x 4 x 18 = 72</span>

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Select the correct answer.<br> Which table shows a proportional relationship between x and y?
wolverine [178]

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Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. Find the dimensions of a norman
Yanka [14]

Answer:

W\approx 8.72 and L\approx 15.57.

Step-by-step explanation:

Please find the attachment.

We have been given that a norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. The total perimeter is 38 feet.

The perimeter of the window will be equal to three sides of rectangle plus half the perimeter of circle. We can represent our given information in an equation as:

2L+W+\frac{1}{2}(2\pi r)=38

We can see that diameter of semicircle is W. We know that diameter is twice the radius, so we will get:

2L+W+\frac{1}{2}(2r\pi)=38

2L+W+\frac{\pi}{2}W=38

Let us find area of window equation as:

\text{Area}=W\cdot L+\frac{1}{2}(\pi r^2)

\text{Area}=W\cdot L+\frac{1}{2}(\pi (\frac{W}{2})^2)

\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W}{2})^2)

\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W^2}{4})

\text{Area}=W\cdot L+\frac{\pi}{8}W^2

Now, we will solve for L is terms W from perimeter equation as:

L=38-(W+\frac{\pi }{2}W)

Substitute this value in area equation:

A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2

Since we need the area of window to maximize, so we need to optimize area equation.

A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2  

A=38W-W^2-\frac{\pi }{2}W^2+\frac{\pi}{8}W^2  

Let us find derivative of area equation as:

A'=38-2W-\frac{2\pi }{2}W+\frac{2\pi}{8}W  

A'=38-2W-\pi W+\frac{\pi}{4}W    

A'=38-2W-\frac{4\pi W}{4}+\frac{\pi}{4}W

A'=38-2W-\frac{3\pi W}{4}

To find maxima, we will equate first derivative equal to 0 as:

38-2W-\frac{3\pi W}{4}=0

-2W-\frac{3\pi W}{4}=-38

\frac{-8W-3\pi W}{4}=-38

\frac{-8W-3\pi W}{4}*4=-38*4

-8W-3\pi W=-152

8W+3\pi W=152

W(8+3\pi)=152

W=\frac{152}{8+3\pi}

W=8.723210

W\approx 8.72

Upon substituting W=8.723210 in equation L=38-(W+\frac{\pi }{2}W), we will get:

L=38-(8.723210+\frac{\pi }{2}8.723210)

L=38-(8.723210+\frac{8.723210\pi }{2})

L=38-(8.723210+\frac{27.40477245}{2})

L=38-(8.723210+13.70238622)

L=38-(22.42559622)

L=15.57440378

L\approx 15.57

Therefore, the dimensions of the window that will maximize the area would be W\approx 8.72 and L\approx 15.57.

8 0
3 years ago
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________=________
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3 0
3 years ago
Read 2 more answers
One of the legs of a right triangle is 9 cm. If the area of the triangle is 225 cm², then the length of the other leg is
ioda

Given:

One of the legs of a right triangle is 9 cm.

The area of the triangle is 225 cm².

To find:

The length of the other leg.

Solution:

The area of a triangle is

Area=\dfrac{1}{2}\times Base\times Height

The area of a right triangle is

Area=\dfrac{1}{2}\times (leg_1)\times (leg_2)

Let x be the length of other leg.

225=\dfrac{1}{2}\times (9)\times (x)

2\times 225=9x

\dfrac{450}{9}=x

50=x

Therefore, the length of the other leg is 50 cm.

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2 years ago
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