PLEASEEE help me!! 2 questions!!

Mathematics

1 answer:

7nadin3 [17]3 years ago

4 0

Answer:

$\frac{\sqrt{15} }{5} \\$ and 16 is a solution to the original equation.

Step-by-step explanation:

To rationalize, you take

$\frac{3 }\sqrt{15}$ times $\frac{\sqrt{15} }{\sqrt{15} }$

This will come out to be $\frac{3\sqrt{15} }{15}$ It then simplifies to $\frac{\sqrt{15} }{5} \\$ .

To cancel out a square root, square both sides. You'll find w = 16

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Smallest of 3 consecutive positive intergers if the product of the smaller two intergers is 5 less than 5 times the largest inte

amm1812

What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)

Three consecutive integers are . . . x, x+1, and x+2

The smallest two are . . . x and x+1
 Their product is . . . . . x(x+1)

5 times the largest one is . . . 5(x+2)
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Now, the conditions of the problem say that x (x + 1) = 5 (x+2) - 5
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You could solve that by factoring it, or use the quadratic equation.

Factored, it says that (x + 1) (x - 5) = 0

From which x = -1
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We only want the positive results, so our three consecutive integers are

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To answer the question, the smallest one is 5 .

Check:

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 30 ? = ? (35) - 5

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ANSWER

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