Check the picture below.
so the lunchbox is really a semi-circle with a radius of 3, sitting on top of a square of 6x6, with a lenght of 10.
the volume of the lunchbox then will be the area of the semi-circle and square times the length.
![\bf \left[ \stackrel{\textit{semi-circle's area}}{\frac{\pi 3^2}{2}}+\stackrel{\textit{square's area}}{(6\cdot 6)} \right]\stackrel{length}{10}\implies \left( \frac{9\pi }{2}+36\right)(10)](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%5B%20%5Cstackrel%7B%5Ctextit%7Bsemi-circle%27s%20area%7D%7D%7B%5Cfrac%7B%5Cpi%203%5E2%7D%7B2%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bsquare%27s%20area%7D%7D%7B%286%5Ccdot%206%29%7D%20%5Cright%5D%5Cstackrel%7Blength%7D%7B10%7D%5Cimplies%20%5Cleft%28%20%20%5Cfrac%7B9%5Cpi%20%7D%7B2%7D%2B36%5Cright%29%2810%29)
What on that be $1
Step-by-step explanation:
because when you add 10 pennies and 9 nickel it will give you one dollars hope it helps ♥️♥️♥️
The measure of arc AC is 40°
Step-by-step explanation:
In any circle the measure of an inscribed angle is one-half the measure of its subtended arc
In circle O
∵ ∠BAC is an inscribed angle subtended by arc BC
∴ m∠BAC = m arc BC
∵ m∠BAC = 70°
- Substitute it in the the expression above
∴ 70 = m arc BC
- Multiply both sides by 2
∴ 140 = m arc BC
∴ The measure of arc BC is 140°
∵ AB is a diameter
- The diameter divides the circle into two equal arcs
∴ m of arc ACB = measure of the circle
- The measure of the circle is 360°
∴ m of arc ACB = (360°)
∴ m of arc ACB = 180°
∵ m arc BC + m arc AC = m arc ACB
∴ 140° + m arc AC = 180°
- Subtract 140 from both sides
∴ m arc AC = 40°
The measure of arc AC is 40°
Answer:
Step-by-step explanation:
Find the roots of x² - 17x - 60
Quadratic formula
x = [17 ± √(17² – 4·1(-60))] / [2·1]
= [17 ± √529] / 2
= [17 ± 23] /2
= -3, 20
x² - 17x - 60 = (x+3)(x-20)
