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2 years ago

Can someone help me with this? this is a substitution method

Mathematics

1 answer:

tigry1 [53]2 years ago

5 0

Answer:

x=0, y = 3/2

Step-by-step explanation:

Ok, for substitution, you need to solve for y in terms of x, I'll do this for the first eqyation

8y=-7x+12

y=-7/8x+3/2, now plug in y in the second equation

-4x+2(-7/8x+3/2)=3, solve for x now

-4x-7/4x+3=3,

-4x-7/4x=0, x=0 now plug in 0 for either equation to solve for y

-4(0)+2y=3

2y=3, y=3/2

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Find the volume of the solid whose base is the region Ix I Iy I < 1 and whose vertical cross sections perpendicular to the y-

gavmur [86]

Answer:

volume of the solid = $\frac{\pi }{3}$

Step-by-step explanation:

As given , the region : |x| + |y| $\leq$ 1

when y $\geq$ 0 ,

|x| + y = 1

⇒|x| = 1 - y

when y ≤ 0 ,

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The given region is the rectangle with sides (0, 5) , (0, -5), (5, 0), (-5, 0)

As given , the vertical cross section are semicircle

As we know that the area of semi circle = $\frac{1}{2}$ $\pi x^{2}$

Now,

Volume = $\int\limits^0_-1 {\frac{\pi }{2} (1+y)^{2} } \, dy$ + $\int\limits^1_0 {\frac{\pi }{2} (1-y)^{2} } \, dy$

= $\frac{\pi }{2} (\frac{(1+y)^{3} }{3} )$ - $\frac{\pi }{2} (\frac{(1-y)^{3} }{3} )$

= $\frac{\pi }{6}$ [1-0] - $\frac{\pi }{6}$ [0-1]

= $\frac{\pi }{6} + \frac{\pi }{6} = 2\frac{\pi }{6} = \frac{\pi }{3}$

⇒volume of the solid = $\frac{\pi }{3}$

4 0

3 years ago

It would mean so much if u help me out on this one!

tia_tia [17]

Answer:the answer should be B :) !

Step-by-step explanation:

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3 years ago

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Elanso [62]

Answer: $11836.8

Step-by-step explanation:

Given. That :

Amount invested = $5000

Interest rate = 9% = 0.09

Period = 10 years, compounded annually

Using the compound interest formula :

A = p(1 + r/n)^nt

A = final amount

P = principal or invested amount

r = rate of interest

n = number of times interest Is applied per period

t = period

A = 5000(1 + 0.09/1)^(1*10)

A = 5000(1.09)^10

A = 5000 * 2.36736367459211723401

A = 11836.81837296058617005

= $11836.8

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3 years ago

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Elanso [62]

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