Find the radius of a circle with area 42.7 units squared.
2 answers:
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Answer: The ratios APBQ : APBC=4:21 and AAQP : AABC= 3:28
Explanation:
Here, ABC is a triangle where, P and Q are the midpoints of the edges AC and AB respectively,
Now, according to the question ,AP:PC=1:3 let AP=x and PC=3x where x is any real number. Thus, AC=AP+AC= x+3x= 4x
Similarly, AQ:QB=3:4 let AQ=3y and QB=4y where y is also any real number. Thus, AB=AQ+QB=3y+4y=7y
Since,
And,