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3 years ago

Find the radius of a circle with area 42.7 units squared.

Mathematics

2 answers:

docker41 [41]3 years ago

6 0

Answer:

3.69

Step-by-step explanation:

$A=\pi r^{2}$ is the formula to find the area of a circle. Input the numbers $42.7=(3.14)r^{2}$ and solve. It equals 3.68765, round to 2 decimal places making it 3.69.

lord [1]3 years ago

3 0

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68% of johns school are boys. There are 180 more boys than girls. How many students are there in johns school

Ghella [55]

Answer:

500 students in the school

Step-by-step explanation:

100 - 68% = 32%

boys percentage 68%

girls percentage 32%

difference 68 - 32 = 36% = 180

36 ÷ 18 = 2 × 50 = 100

180 ÷ 18 = 10 × 50 = 500

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8(5) - 4y = 39
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3 years ago

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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3 years ago

How do I do problems 4-6

maria [59]

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