Let "a" and "b" represent the values of the first and second purchases, respectively.
0.40*(original price of "a") = $10
(original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
a = $25.00 -10.00 = $15.00
At the other store,
$29 = 0.58b
$29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate
Then Julia's total spending is
a + b = $15.00 +50.00 = $65.00
Julia spent $65 in all at the two stores.
It is 6 sq. units. I hope you do well. Have a wonderful day.
Part a)
a) The given function is

We let

Interchange x and y.

Solve for y;



Part b) The range of f(x) refers to y-values for which f(x) exists.
The range of f(x) is

This is because the function is within y=-3 and y=3.
c) The range of

is

The domain is -3≤x≤3
This is because the domain and range of a function and its inverse swaps.
Part d) The graph is shown in the attachment.
Wait doesn’t it tell you how to solve it tho