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Katarina [22]
3 years ago
8

Brandi completed 7 out of her 9 chores. What percent does she have left to finish?

Mathematics
2 answers:
Anni [7]3 years ago
7 0

sorry dont mind this I answered the wrong question

sineoko [7]3 years ago
4 0

Answer:

12%

Step-by-step explanation:

I'm not 100% sure, but I did 9/7, and multiplied by 10 to get %

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SOS I'm terrible at math.
Tresset [83]
<span>y = -5 cos x is a basic (simple) variation of the basic trig function y = cos x.

The given </span>y = -5 cos x could be re-written as <span>y = -5 cos 1x.
Compare this to the most general form:          y =  a cos bx.

Here we see that the coefficient b equals 1.

There is a rule for finding the period of such a function:  Period = 2pi/b.

Since b = 1 here, the Period here is 2pi/1, or simply 2pi.

Please stop saying "I'm terrible with math."  That does not help you at all.  Say, instead, "With just a little help I could understand this just fine."</span>
5 0
3 years ago
What value of n makes the equation true?
otez555 [7]
2/3 n = -12 Write equation

(3/2) 2/3n = -12/1 (3/2) Isolate n

n = -36/2 Simplify

n = -18 Answer




4 0
3 years ago
Read 2 more answers
What of the following best describes the shape of the graph​
Assoli18 [71]

Answer:

I have no idea

Step-by-step explanation:

This question doesn't have enough information for me to answer it.

7 0
3 years ago
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9<br> 2<br> 199843x199813996<br> 1998-1998
Mashutka [201]

Answer:

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5 0
3 years ago
Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares
FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

\frac{24}{2}=\frac{24}{1+e^{-1.3x}}

⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

                             ⇒ log 3=-1.3x

                             ⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82


5 0
3 years ago
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