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vodomira [7]
3 years ago
9

Jin needs to fence in his rectangular backyard. The fence will have one long section away from, but parallel to, the length of h

is house and two shorter sides connecting that section to the house. The length of Jin’s house is (3x+ 4) yd and the area of his backyard is (9x2+ 15x+ 4) yd^2. How many yards of fencing will Jin need?
A. (6x+ 2) yd C. (9x+ 6) yd
B. (9x+ 9) yd D. (12x+ 10) yd hint: ^2 means squared.
Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0

Answer: C. 9x+6 yd


Step-by-step explanation:

Given: The length of Jin's house= 3x+4\ yd

The area of Jin's backyard=9x^2+15x+4\ yd^2

By middle splitting method, The area of Jin's backyard=9x^2+12x+3x+4\ yd^2=(3x+1)(3x+4)\ yds

To find the width of the backyard, divide the area by the length, we get

Width=\frac{(3x+1)(3x+4)}{(3x+4)}=3x+1

According to the question, only three sides need to fence

Fencing=3x+1+3x+1+3x+4=9x+6\ yd

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