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3 years ago

A blueprint for a house has a scale factor n = 45. A wall in the blueprint is 5 in. What is the length of the actual wall

Mathematics

1 answer:

Mars2501 [29]3 years ago

8 0

Answer:

The length of the actual wall is 405 inches or 33.75 feet

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What kind of line is being constructed in this series of diagrams?

wolverine [178]

The line that is being constructed in the series of diagrams provided is perpendicular.

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3 years ago

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How do you factor 7+14

mote1985 [20]

You could factor a 7 out of 7 + 14 to get 7(1 + 2).

This would equal the same thing as 7 + 14, which is 21.

7 * 3 = 21.

21 can be factored like so:

1 * 21 = 21

3 * 7 = 21

5 0

3 years ago

PLEASE SHOW FULL SOLUTIONS!!! WILL MARK BRAINLIEST FOR BEST ANSWER!!

Lubov Fominskaja [6]

Answer:

The first option: $265.05

Step-by-step explanation:

<h3>Option 1</h3>

<u>Payment as sequence:</u>

11.75, 12.10, 12.45, ...

The first term a = 11.75
Common difference d = 0.35
Number of terms n = 18

<u>Find the sum of the first 18 terms:</u>

S₁₈ = (a + a₁₈)*18/2 = (a + a + 17d)*9 = (11.75*2 + 17*0.35)*9 = $265.05

<h3>Option 2</h3>

Flat rate $14.50 per hour

$14.50*18 = $261.00

<u>Compared, we see the first option pays more:</u>

$265.05 > $261.00

5 0

2 years ago

6^3+5(8+0.2)= can someone tell me the steps i know its 257 i need the steps

Sav [38]

Step 1 distribute the 5 across (8+0.2)

6^3+5(8+0.2)

6^3+40+1

6^3+41 (<em>I simplified the +40 and the +1</em>)

Step 2 take 6 to the power of 3

6^3+41

6x6x6 6x6=36 36x6=216

216+41 (<em>Simplify!</em>)

257

I hope this helped!

3 0

3 years ago

Distances in space are measured in light-years. The distance from Earth to a star is 6.8 × 1013 kilometers. What is the distance

baherus [9]

I light year = 9.46 x 10¹² km

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Find the number of light years
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$\text {Number of light years = } \dfrac{6.8 \times 10^{13}}{9.46 \times 10^{12}}$

$\text {Number of light years = } 7.18$

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Answer: The distance from Earth to the star is 7.18 light-years.
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2 years ago

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