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3 years ago

I need help asapppplpplll

Mathematics

1 answer:

My name is Ann [436]3 years ago

7 0

Answer:

sqrt( 3 V / pi h) =r

Step-by-step explanation:

V = 1/3 pi r^2 h

Multiply each side by 3

3 V = 1/3 pi r^2 h*3

3 V = pi r^2 h

Divide each side by pi h

3 V/ pi h = pi r^2 h/ pi h

3 V/ pi h = r^2

Take the square root of each side

sqrt( 3 V / pi h) = sqrt(r^2)

sqrt( 3 V / pi h) =r

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The fair spinner shown in the diagram above is spun.

julsineya [31]

Answer:

1/5

Explanation:

There are five choices in the spinner. <em>One </em>of the choices is labeled '5'. That means you will have one out of the 5 choices to get the choice labeled '5'.

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3 years ago

Evaluate 0.3 + y/2 when y = 10 and z =5

Vladimir79 [104]

Answer:

0.3*10+10/5

PEMDAS (left to right)

3+2

Step-by-step explanation:

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3 years ago

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I NEED HELP WITH THIS!!<br> Question: solve the one-step equation.<br> r-6=7

scoray [572]

Answer:

r = 13

Step-by-step explanation:

r-6=7

Add 6 to each side

r-6+6=7+6

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3 years ago

Read 2 more answers

Solve for x: 3-x = 3(6x-9). Describe the process used to solve the equation and show each step.

FromTheMoon [43]

Answer:

$x=1.578$

Step-by-step explanation:

Given equation is $3-x = 3(6x-9)$

We need to find the value of $x$

$3-x = 3(6x-9)$

Distribute $3$ in the right-hand side

$3-x=18x-27$

Add both sides $x$

$3-x+x=18x+x-27\\3=19x-27$

Now, add both sides $27$

$3+27=19x-27+27\\30=19x$

Divide both sides by $19$

$\frac{30}{19}=\frac{19x}{19}\\x=1.578$

So, $x=1.578$

5 0

3 years ago

The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area i

lorasvet [3.4K]

Answer:

The area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by $A=l w$

Derivative w.r.t 't',

$\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}$

Now, we have given

$\frac{dl}{dt}=3\ cm/s$

$l=5\ cm$

$\frac{dw}{dt}=2\ cm/s$

$w=4\ cm$

Substitute all the values,

$\frac{dA}{dt}=(4)(3)+(5)(2)$

$\frac{dA}{dt}=12+10$

$\frac{dA}{dt}=22\ cm^2/s$

Therefore, the area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

4 0

3 years ago