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lesya692 [45]
3 years ago
9

Write an equation that models this situation. A copier that makes 34 copies per minute runs for 12 minutes. How many copies (x)

are made during that time?
Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
4 0

Answer:

x = 34t

408

Step-by-step explanation:

x = 34t

x: no. of copies

t: minutes

x = 34(12)

x = 408

vazorg [7]3 years ago
3 0

Answer:

x

34

= 12

x = total number of copies

total number of copies

copies per minute

= number of minutes copier runs

B )  x / 34 = 12  is correct

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Divide the numerator and denominator by their gcd which is 5
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can someone help me simplify this: the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the th
VMariaS [17]
10x^6y^3 + 20x^3y^2 / 5x^3y = 
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<span>2x^3y^2 + 4y
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First you find what the expressions 10x^6y^3 and 20x^3y^2 have in common, and that is 5x^3y, which is the same as the denominator, so you can easily divide them and get 1. 
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8 0
4 years ago
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CaHeK987 [17]
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4 0
3 years ago
What is the value of n in the equation 3n + 2(n + 2) = 9n + 12?
Alex777 [14]
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6 0
3 years ago
M is a directly proportional to r cubed when r=4 M=160
Paraphin [41]

Answer:

1) When r = 2, M = 20.

2) When M  = 540, r = 6.

Step-by-step explanation:

M is a directly proportional to r cubed

This means that the equation for M has the following format:

M = ar^3

In which a is a multiplier.

When r=4 M=160.

We use this to find a. So

M = ar^3

160 = a(4^3)

64a = 160

a = \frac{160}{64}

a = 2.5

So

M = 2.5r^3

1) work out the value of M when r=2

M = 2.5*2^3 = 2.5*8 = 20

When r = 2, M = 20.

2) work out the value of r when M=540

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540 = 2.5r^3

r^3 = \frac{540}{2.5}

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r = \sqrt[3]{216}

r = 6

When M  = 540, r = 6.

7 0
3 years ago
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