2/3
Divide the numerator and denominator by their gcd which is 5
10x^6y^3 + 20x^3y^2 / 5x^3y =
5x^3y (2x^3y^2 + 4y) / 5x^3y=
<span>2x^3y^2 + 4y
</span>
First you find what the expressions 10x^6y^3 and 20x^3y^2 have in common, and that is 5x^3y, which is the same as the denominator, so you can easily divide them and get 1.
<span>Hope you understand!
</span>
If your asking for the answer it’d be
x= -1
3n+2n+4=9n+12
5n+4=9n+12
4-12=9n-5n
-8=4n
Divide both sides by 4
n=-2
Answer:
1) When r = 2, M = 20.
2) When M = 540, r = 6.
Step-by-step explanation:
M is a directly proportional to r cubed
This means that the equation for M has the following format:

In which a is a multiplier.
When r=4 M=160.
We use this to find a. So





So

1) work out the value of M when r=2

When r = 2, M = 20.
2) work out the value of r when M=540




![r = \sqrt[3]{216}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B216%7D)

When M = 540, r = 6.