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pshichka [43]
3 years ago
9

In a park, a sidewalk is built around the edge of a circular garden as shown below. The sidewalk is 5 feet wide, and the garden

measures 20 feet across. Which measurement is closest to the circumference of the outer edge of the sidewalk?
A.
75ft

B.
90ft

C.
30ft

D.
700ft
Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

B.  90ft

Step-by-step explanation:

-The diameter of the outer edge will be equivalent to the garden's diameter plus twice the sidewalk's width:

D=D_g+2W_s\\\\=20+2\times5\\\\=30\ ft

#The outer circumference can then be calculated as:

C=\pi D\\\\=30\PI\\\\=94.25\ ft

Hence, the measurement closest to this circumference value is 90 ft

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State whether the conjecture is true or false. If false provide a counter example
olganol [36]

Answer:

The Associative property does not hold for the division of whole numbers.

Step-by-step explanation:

If ‘a’, ‘b’, and ‘c’ are the three whole numbers then, a ÷ (b ÷ c) ≠ (a ÷ b) ÷ c ⇒ 100 ÷ (25 ÷ 5) = 20 ≠ (100 ÷ 25) ÷ 5 = 4 ÷ 5. Easy Way to Remember the Properties of Whole Numbers

5 0
3 years ago
43/14 as decimal rounded to nearest hundredth
anzhelika [568]

Answer:The answer would be 3.07.


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Hope this helps!



5 0
3 years ago
Read 2 more answers
A sporting goods factory produced 13,234 tennis balls per month.How many tennis balls does it produce during 12 months?​
Lyrx [107]

Answer:

158,808 !

Step-by-step explanation:

13,234 × m (months)

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= 158,808

6 0
3 years ago
15cm<br> 12cm<br> Shown is a right-angled triangle.<br> Work out the area of the triangle
tiny-mole [99]

Answer: The answer is either 90

Step-by-step explanation:

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7 0
3 years ago
Use the Venn diagram to calculate probabilities.
Rudiy27

<u>Corrected Question</u>

These are the given probabilities. The Venn diagram is also attached. are (A) P(A|C) = 2/3

(B) P(C|B) = 8/27

(C) P(A) = 31/59

(D) P(C) = 3/7

(E) P(B|A) = 13/27

Answer:

A and C

Step-by-step explanation:

P(A|C)=\dfrac{P(A\cap C)}{P(C)}= \dfrac{14/59}{21/59}=\dfrac{14}{21}=\dfrac{2}{3}

P(C|B) =\dfrac{P(C\cap B)}{P(B)}= \dfrac{11/59}{27/59}=\dfrac{11}{27}\neq \dfrac{8}{27}\\\\P(A) = \dfrac{31}{59}\\\\P(C) =\dfrac{21}{59}\neq \dfrac{3}{7}\\\\P(B|A)=\dfrac{P(B\cap A)}{P(A)}= \dfrac{13/59}{31/59}=\dfrac{13}{31}\neq\dfrac{13}{27}

From the above, only A and C are correct.

8 0
3 years ago
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