How can I prove that
1 answer:
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The speed of plane 1 will be 300 miles/sec and that of plane 2 will be 600 miles/sec.
We have two planes flying in opposite directions to each other.
We have to determine how fast was the each plane flying.
<h3>What is the formula to calculate the distance covered by the object moving with speed - x m/s in time - t s ?</h3>The formula to calculate the distance travelled will be -
distance = speed x time = (t) meters
According to the question -
Let us assume that the speed of plane 1 = v miles/sec.
Then, the speed of plane 2 will be = 2v miles/sec.
Distance covered by plane 1 in 3 hours will be = 3v miles.
Distance covered by plane 2 in 3 hours will be = 3 x (2v) miles = 6v miles.
Since they are 2700 miles apart after three hours, therefore -
3v + 6v = 2700
9v = 2700
v = 300 miles/sec
Hence, the speed of plane 1 will be 300 miles/sec and that of plane 2 will be = 2v = 2 x 300 = 600 miles/sec.
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You did not provide a table however I used
x y
0 -1
3 1
(I tried to make a table above with x,y)
The x intercept is (3/2, 0)
The y intercept is (0, -1)
Slope 2/3
See pic for graph
x y
0 -1
3 1
(I tried to make a table above with x,y)
The x intercept is (3/2, 0)
The y intercept is (0, -1)
Slope 2/3
See pic for graph