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nexus9112 [7]
3 years ago
7

How can I prove that

Mathematics
1 answer:
Citrus2011 [14]3 years ago
6 0

I can prove by being smart then that if you tell me all the ansers

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If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
SVEN [57.7K]
(g-f)(x)=g(x)=f(x)

(g-f)(x)=6x-4+x^2

(g-f)(x)=x^2+6x-4  then:

(g-f)(3)=3^2+6*3-4

(g-f)(3)=9+18-4

(g-f)(x)=23
7 0
3 years ago
The store,s rectangular floor is 42 meters long and 39 meters wide. How many square meters of flooring do they need? Use estimat
Helga [31]
We have to find the area of the floor in order to know how many square meters of flooring they need.

The area of the floor is:
42 m* (39 m)= 1,638 m^(2)

They need 1,638 m^(2) of flooring.

Hope this helps~
8 0
3 years ago
Read 2 more answers
Complete factorization f(x)=x^4-x^3-5x^2-x-6
Marianna [84]

The solution to the above  factorization problem is given as f′(x)=4x³−3x²−10x−1. See steps below.

<h3>What are the steps to the above answer?</h3>

Step 1 - Take the derivative of both sides

f′(x)=d/dx​​(x^4−x^3−5x^2−x−6)

Step 2 - Use differentiation rule d/dx​(f(x)±g(x))=d/dx​(f(x))±d/dx​(g(x))

f′(x)=d/dx​​(x4)−d/dx​​(x^3)−d/dx​​(5x^2)−d/dx​​(x)−d/dx​​(6)

f′(x)=4x^3−d/dx​​(x3)−d/dx​​(5x^2)−d/dx​​(x)−d/dx​​(6)

f′(x)=4x^3−3x2−d/dx​​(5x^2)−d/dx​​(x)−d/dx​​(6)

f′(x)=4x^3−3x^2−10x−d/dx​​(x)−d/dx​​(6)

f′(x)=4x^3−3x^2−10x−1−dxd​(6)

f′(x)=4x^3−3x^2−10x−1−0

Learn more about factorization:
brainly.com/question/25829061
#SPJ1

5 0
2 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
2 years ago
Help me please!! will mark brainliest!
WITCHER [35]
10 hours seems like the most reliable answer because it matches up the best
8 0
3 years ago
Read 2 more answers
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