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RUDIKE [14]
3 years ago
5

How to solve x in a step by step response

Mathematics
2 answers:
ivanzaharov [21]3 years ago
5 0

Step 1: Simplify both sides of the equation.<span><span><span>x2</span>−7</span>=9</span><span>Simplify: (Show steps)</span><span><span><span><span>12</span>x</span>−7</span>=9</span>Step 2: Add 7 to both sides.<span><span><span><span><span>12</span>x</span>−7</span>+7</span>=<span>9+7</span></span><span><span><span>12</span>x</span>=16</span>Step 3: Multiply both sides by 2.<span><span>2*<span>(<span><span>12</span>x</span>)</span></span>=<span><span>(2)</span>*<span>(16)</span></span></span><span>x=32</span><span>
</span>
dmitriy555 [2]3 years ago
4 0
X/2 - 7=9
Add 7 to both sides so that it cancels out the -7
x/2= 16
Multiply both sides by 2 so that the only thing remaining on the left side is the variable x.
Final Answer: x=32
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Read 2 more answers
The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
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Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

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