Answer:
B. x ≥ 3 or x ≤ −2
Step-by-step explanation:
<u>Inequalities</u>
Solve the inequality:

Subtracting 6:

Factoring:
(x-3)(x+2) ≥ 0
We have a product that must be greater or equal to 0. This can only happen if:
x - 3 ≥ 0 and x + 2 ≥ 0
Or:
x - 3 ≤ 0 and x + 2 ≤ 0
The first couple of conditions yields to:
x ≥ 3 and x ≥ -2
Which lead to the solution
x ≥ 3 [1]
The second couple of conditions yields to:
x ≤ 3 and x ≤ -2
Which lead to the solution
x ≤ -2 [2]
The final solution is [1] or [2]:
Answer:
B. x ≥ 3 or x ≤ −2
Check the picture below.
so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).
because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

I’m pretty sure this is the answer
128, -256
-3x² + 3y² + 4x + 4x² - 4y + 2
Add like terms.
x² + 3y² + 4x - 4y + 2
So the answer is D.