Answer:
The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Step-by-step explanation:
We are given that 
Standard deviation,  ounces
ounces
We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

Assume the bag weight distribution is bell-shaped
Therefore,

We know that 

Using the value of z
Now,




Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
 
        
             
        
        
        
.2 per treat 2 cents per treat
        
                    
             
        
        
        
So if we take 1/4 to be the 100%, what is 2/3 in percentage off of it then?

yes, is a large value, because 2/3 is indeed larger than 1/4, more than twice as large.
 
        
        
        
3/2 since you move 3 spaces horizontally (x) and 2 spaces up (y)
        
             
        
        
        
Yes. it is the largest number