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ioda
3 years ago
11

Can someone help me with this bonus question for me

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

i cant read it well can u type it so i can answer ?

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Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po
Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, \sigma=0.2ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

P(x\geq 10)=0.99

Assume the bag weight distribution is bell-shaped

Therefore,

P(\frac{x-\mu}{\sigma}\geq 10)=0.99

We know that

z=\frac{x-\mu}{\sigma}

Using the value of z

Now,

\frac{10-\mu}{0.2}=0.99

10-\mu=0.99\times 0.2

\mu=10-0.99\times 0.2

\mu=9.802

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0
3 years ago
Please help I will mark brainly
vivado [14]
.2 per treat 2 cents per treat
5 0
3 years ago
Read 2 more answers
2/3 is what percent of 1/4?
saveliy_v [14]
So if we take 1/4 to be the 100%, what is 2/3 in percentage off of it then?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{4}&100\\\\
\frac{2}{3}&p
\end{array}\implies \cfrac{\frac{1}{4}}{\frac{2}{3}}=\cfrac{100}{p}\implies \cfrac{1}{4}\cdot \cfrac{3}{2}=\cfrac{100}{p}\implies \cfrac{3}{8}=\cfrac{100}{p}
\\\\\\
p=\cfrac{8\cdot 100}{3}\implies p=\cfrac{800}{3}\implies p=266\frac{2}{3}\implies p\approx 266.\overline{66}

yes, is a large value, because 2/3 is indeed larger than 1/4, more than twice as large.
8 0
3 years ago
Find the slope of the graph
olga55 [171]
3/2 since you move 3 spaces horizontally (x) and 2 spaces up (y)
3 0
2 years ago
Is 267 the largest number in the sum of 3 integers evaluated from 269?
Anni [7]
Yes. it is the largest number

4 0
3 years ago
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