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trapecia [35]
3 years ago
9

!!!!URGENT URGENT GEOMETRY REFLECTIONS!!! PROVIDE EXPLANATION IF POSSIBLE THANKS. BOGUS ANSWERS WILL BE REPORTED

Mathematics
1 answer:
marta [7]3 years ago
5 0

If m is the midpoint between x=a and x=b, then you have

... (a+b)/2 = m

... a+b = 2m

... b = 2m - a

For the case where a=1 and m=6, we find the reflected coordinate to be

... 2·6 - 1 = 11

Now, we want to reflect about the line x=4, so a=11 and m=4. The second reflection results in an x-coordinate of

... 2·4 - 11 = -3

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Find the x- and y-intercepts of the graph of the linear equation −4x+8y=−16.
Bogdan [553]
Put it in slope form: y=mx+b
8y= 4x-16
Divide by 8
Y = 1/2x -2
1/2 is x intercept and -2 is y intercept
8 0
3 years ago
Which of the following values are in the range of the function graphed below? check all that apply
vodomira [7]

Answer:

Option D. 1

Option E. 1/2

Step-by-step explanation:

we know that

Looking at the graph

The domain is the interval ----> [-1,1]

-1\leq x\leq 1

The domain is all real numbers greater than or equal to -1 and less than or equal to 1

The range is the interval ----> [0,1]

0\leq y\leq 1

The range is all real numbers greater than or equal to 0 and less than or equal to 1

therefore

The values that are in the range are

1 and 1/2

5 0
3 years ago
Read 2 more answers
Urgent please ans this​
Rama09 [41]

Answer:

x=6

Step-by-step explanation:

Remember, the formula for area is the length times the width. So, if we know the width is 3, and we know the total area is 24, all we need to do is divide 24 by 3 to get 8. 8 is the split up side, the one that is x + 2. To find x, simply subtract 2 from 8. 8 - 2=6.

24/3=8

8-2=6

3 0
3 years ago
Ten times the number, x, is one-half the sum of the number and three
Mazyrski [523]
10x=1/2x+3

I think it's right, but not 100% sure
7 0
3 years ago
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Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

7 0
3 years ago
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