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3 years ago

If a pyramid had a base of area 4 and height of 6, what is the volume

Mathematics

2 answers:

lilavasa [31]3 years ago

4 0

24 because 4x6 is 24

aleksley [76]3 years ago

3 0

I believe this is 24

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Can you help I’ll mark brainliest

Marta_Voda [28]

Answer:

$7\sqrt{3}$

Step-by-step explanation:

Since this is a 30-60-90 triangle, we know that the sides have the following characteristic:

The side opposite to 30 degree angle: n

The side opposite to 60 degree angle: $n\sqrt{3}$

The side opposite to 90 degree angle: 2n

Since we know that 7 is opposite to 30-degree, and x is opposite to 60 degree, than we know that x = $7\sqrt{3}$

6 0

3 years ago

When purchased, a plastic beach ball is deflated and packaged flat. The package states that when inflated to its maximum capacit

Zigmanuir [339]

So the formula for a volume of a sphere is 4/3 times pi times the radius cubed.
step one: 4/3 times 3.14 = 4.18666666667
Step two: then you cube 8.5 and get 592.45
the final answer is 2,480.3906

6 0

3 years ago

Determine the number of subsets of {12, 13, 14}

Alex787 [66]

Answer:

Step-by-step explanation:

{ }

{12} {13} {14}

{12, 13} {12, 14} {13,14}

{12, 13, 14}

Total: 8

7 0

2 years ago

What is 43 x 34/ 28-14= <br> this /stands for a division sine

Sergio [31]

This is the answer 104.4285714285714

6 0

3 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

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