The measure of a central angle is equal to measure of a minor arc. That makes m<GEH=17x+12. By the Vertical Angles Theorem, m<GEH and m<IEF are equal to each other (m<GEH=17x+12=m<IEF). By the same theorem, m<FEG and m<IEH are also equal (m<FEG=8x-7=m<IEH). The angles in a circle must all add up to 360 degrees, 2(17x+12)+2(8x-7)=360. Solve for x, then plug x into the equation for m<IEF.
Hope this helps!
Answer:
SSS
Step-by-step explanation:
XW = YZ by reflective the line
XY = WZ by the two lines
and XZ = XZ by reflective property of congruence
Answer:
a. p1(x) = 2 - x
b. p2(x) = x² - 3*x + 3
c. p1(0.97) = 1.03; p2(0.97) = 1.0309
Step-by-step explanation:
f(x) = 1/x
f'(x) = -1/x²
f''(x) = 2/x³
a = 1
a. The linear approximating polynomial is:
p1(x) = f(a) + f'(a)*(x - a)
p1(x) = 1/1 + -1/1² * (x - 1)
p1(x) = 1 - x + 1
p1(x) = 2 - x
b. The quadratic approximating polynomial is:
p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²
p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²
p2(x) = 2 - x + (x - 1)²
p2(x) = 2 - x + x² - 2*x + 1
p2(x) = x² - 3*x + 3
c. approximate 1/0.97 using p1(x)
p1(0.97) = 2 - 0.97 = 1.03
approximate 1/0.97 using p2(x)
p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309
Dy/dx= tanx, can be answered directly using the derivatives of trigonometric functions but this is how the answer is derived
=(sinx/cosx) basic trigonometric function
= [cosx cox+sinxsinx]/cos^2x
=[cos^2x+sin^2x]/cos^2x
cos^2+sin^2x = 1 ; fundamental trigonometric identities
= 1/cos^2x; reciprocal relations
= sec^2x+C
The answer is letter B.sec^2x+C
