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sergij07 [2.7K]
3 years ago
15

Help please, 25 points

Mathematics
1 answer:
amm18123 years ago
8 0

Answer:

Step-by-step explanation:

C

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PLEASE HELP<br><br> A<br><br> B<br><br> C<br><br> OR<br><br> D
iVinArrow [24]

Answer:

36 cm

Step-by-step explanation:

P = 2l + 2w

Plug in

P = 2(14) + 2 (4)

P = 28 + 8

P = 36

5 0
4 years ago
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A 340 m wire is cut into three pieces. The second piece is 4 times as long as the first. The third piece is 3 times as long as t
USPshnik [31]

Answer: total length 5780

Step-by-step explanation:

1st wire. 340m

2nd wire. 1360m

3rd wire. 4080

3 0
3 years ago
Which equation has infinite solutions?
AnnyKZ [126]

The equation that has an infinite number of solutions is 2x + 3 = \frac{1}{2}(4x + 2) + 2

<h3>How to determine the equation?</h3>

An equation that has an infinite number of solutions would be in the form

a = a

This means that both sides of the equation would be the same

Start by simplifying the options

3(x – 1) = x + 2(x + 1) + 1

3x - 3 = x + 3x + 2 + 1

3x - 3 = 4x + 3

Evaluate

x = 6 ----- one solution

x – 4(x + 1) = –3(x + 1) + 1

x - 4x - 4 = -3x - 3 + 1

-3x - 4 = -3x - 2

-4 = -2 ---- no solution

2x + 3 = \frac{1}{2}(4x + 2) + 2

2x + 3 = 2x + 1 + 2

2x + 3 = 2x + 3

Subtract 2x

3 = 3 ---- infinite solution

Hence, the equation that has an infinite number of solutions is 2x + 3 = \frac{1}{2}(4x + 2) + 2

Read more about equations at:

brainly.com/question/15349799

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<u>Complete question</u>

Which equation has infinite solutions?

3(x – 1) = x + 2(x + 1) + 1

x – 4(x + 1) = –3(x + 1) + 1

2x + 3 = \frac{1}{2}(4x + 2) + 2

\frac 13(6x - 3) = 3(x + 1) - x - 2

5 0
2 years ago
X^2-10x+8=0 by completing the square
OverLord2011 [107]
When completing the square <span>x=9.12311 and </span><span>x=<span>0.876894</span></span>
4 0
3 years ago
Find a third degree polynomial function of the lowest degree that has the zeros below and whose leading coefficient is one.
Tanzania [10]

Answer:

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is p(x) = x^{3}-5\cdot x^{2}-6\cdot x.

Step-by-step explanation:

From Fundamental Theorem of Algebra, we remember that the degree of the polynomials determine the number of roots within. Since we know three roots, then the factorized form of the polynomial function with the lowest degree is:

p(x) = (x-r_{1})\cdot (x-r_{2})\cdot (x-r_{3}) = 0 (1)

Where r_{1}, r_{2} and r_{3} are the roots of the polynomial.

If we know that r_{1} = -1, r_{2} = 0 and r_{3} = 6, then the polynomial function in factorized form is:

p(x) = (x+1)\cdot x \cdot (x-6) (2)

And by Algebra we get the standard form of the function:

p(x) = x\cdot (x+1)\cdot (x-6)

p(x) = x\cdot (x^{2}-5\cdot x -6)

p(x) = x^{3}-5\cdot x^{2}-6\cdot x (3)

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is p(x) = x^{3}-5\cdot x^{2}-6\cdot x.

6 0
3 years ago
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