Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109
Using AP, T(n)=15+11+7+....-129
T(n)=19-4n => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
Answer:
Height of the student=1.651m
Step-by-step explanation:
Given: Height of a student= 65.0 inch.
To find: Height of a student in meters.
Solution:
We know that 1 inch=2.54 cm, then
65.0 inch will be =
65.0 inch will be=
Also, we know that 1cm=
, then
165.2 cm will be equal to=
165.2 cm will be equal to=
Therefore, the height of a student in meters will be 1.651 meters.
Answer:
It is Linear because it runs in a straight line
Step-by-step explanation:
About 190% because its almost two times the original number
I hope that answers your question
Looks like you've got 3 lines that are all parallel with one transversal diagonally running down the middle.
Since all of the other lines are parallel to one another, there are only two different angle combinations to be made by the transversal and one of the other lines, one of which being the given 60º angle.
The other one is found by subtracting that from 180 since a straight angle measures 180º.
180 - 60 = 120
The smaller ones are always 60º, and the larger ones are always 120º.
That means that a = 60, b = 60, and d = 60
It also means that c = 120 and e = 120.
Hope this helps!
