3 years ago

If X and Y are random variables, the sum of all the conditional probabilities of X given a specific value of Y will always be:

1 answer:

5 0

What library are you using?

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vekshin1

It means the exact number

7 0

3 years ago

Helga [31]

Answer:

Step-by-step explanation:

8 0

2 years ago

Nadya [2.5K]

4/5 is the answer unless you need it in decimal

5 0

3 years ago

photoshop1234 [79]

Substitute $u=x^2+4$ and $du=2x\,dx$ . Then the integral transforms to

$\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \int \frac{du}{u^3}$

Apply the power rule.

$\displaystyle \int \frac{du}{u^3} = -\dfrac1{2u^2} + C$

Now put the result back in terms of $x$ .

$\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \left(-\dfrac1{2u^2} + C\right) = -\dfrac1{4u^2} + C = \boxed{-\dfrac1{4(x^2+4)^2} + C}$

3 0

2 years ago

pshichka [43]

the common difference is two of course

3 0

3 years ago