Answer:
Probability of each situation is 1/3 .
Step-by-step explanation:
There are 3 possibilities
1- Train will arrive early
2- Train will arrive on time
3- Train will arrive late
Formula for Probability of event a is = n(a)/Sum of events
In this case sum of events = 3
So
Probability of early arrival = 1/3
Probability of on time arrival = 1/3
Probability of late arrival = 1/3
We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA=

. Hence CM=GC+GM=3*

. Now, since GM is normal to AB, we have by the pythagoeran theorem that:

Hence, we calculate from this that AC^2= 28, hence AC=2*

=BC. Thus, the perimeter of the triangle is 2+4*

.
First term is -7, so a_1 = -7
To get the next term, we add on 4. We can see this if we subtract like so
d = (2nd term) - (1st term) = (-3) - (-7) = -3+7 = 4
So d = 4 is the common difference.
Apply a_1 = -7 and d = 4 to get...
a_n = a_1 + d*(n-1)
a_n = -7 + 4*(n-1)
a_n = -7 + (n-1)*4
Answer: Choice A
Answer:
(3,2)
Step-by-step explanation:
Answer:
4/5.
Step-by-step explanation:
would you mind looking at my question :)