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cricket20 [7]
3 years ago
14

Recall the following study: Over a 17-year period researchers studied a sample of 707 individuals from a single community. They

recorded the number of hours each individual spent watching television during adolescence and early adulthood. In later years, they recorded the number of aggressive acts by individuals in the study, as reported by parents, teachers and police. Science magazine published the results in 2002 in an article titled "Television Viewing and Aggressive Behavior during Adolescence and Adulthood." Which of the following variables could not confound the results of this study?
a. gender.
b. parental supervision and other aspects of family life.
c. poverty and neighborhood conditionds.
d. the amount of television the adolescents watch.
Mathematics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

Hence the answer is option c ; poverty and neighborhood conditions

Step-by-step explanation:

From the research, it is well known that both the dependent variable and independent variable will be taken into consideration before arriving at a conclusion.

A dependent variable is the variable that is been studied or measured i.e the results of a scientific research.

An independent variable is a variable that is been altered or controlled for and whose effects are compared to the results of the dependent variable, as such the results of  a dependent variable is dependent on the alteration of the parameters of an independent variable.

From the question ; the dependent variable is sample of 707 individuals from a single community while the independent variable ; the number of hours each individual spent watching television during adolescence and early adulthood.

The word confound in statistics implies a variable which has a greater effects on both the dependent and the independent variable.

Hence the answer is option c ; poverty and neighborhood conditions

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Please answer this correctly
Ymorist [56]

B; 25.65+13.23+6.35=45.23

To do this mentally just add the 2 decimals places together first (1.23). Then just add the whole numbers (44). Then add the 2 numbers together, 44+1.23=45.23

8 0
3 years ago
20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st
Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

8 0
3 years ago
Find area of the shape
pentagon [3]
The answer is a. You find the area of each shape and add them
4 0
3 years ago
A room has three lightbulbs. Each one has a 30% probability of burning out within the month. Write the probability as a percenta
lesantik [10]

Answer:

97.3%

Step-by-step explanation:

Let the three bulbs be A, B and C respectively.

Let P(A) denote the probability that the first bulb will burn out

Let P(B) denote the probability that the second bulb will burn out

Let P(C) denote the probability that the third bulb will burn out

Now, we are told that Each one has a 30% probability of burning out within the month.

Thus;

P(A) = P(B) = P(C) = 30% = 0.3

Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;

P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))

P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%

3 0
3 years ago
PLEASE!!! HELP NEEDED!!!
andriy [413]

Answer:

  (x, y) = (-1, 3), (-3, 115), (2, 0)

Step-by-step explanation:

The first two test points are <em>not roots</em>. The last one is a root.

4 0
3 years ago
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