The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:
![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
#SPJ1
Yes because 18% is an abbysmal amount for a tip
Answer:
Step-by-step explanation:
Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.
2p - 3q = 4 ...................... 1 * 3
3p + 2q = 9 ..................... 2 * 2
Multiplying equation 1 by 3 and 3 by 2:
6p - 9q = 12
6p + 4q = 18
Subtracting both equation
-9q-4q = 12-18
-13q = -6
q = -6/-13
q = 6/13
Substituting q = 6/13 into equation 2
2p - 3(6/13) = 4
2p - 18/13 = 4
2p = 4+18/13
2p = (52+18)/13
2p = 70/13
p = 70/26
p = 35/13
<em>Hence p = 35/13 and q = 6/13</em>
<em></em>
<em>b) </em>If if 223ₓ = 87 find x
Using the number base system and converting 223ₓ to base 2 will give us;
223ₓ = 2*x² + 2*x¹ + 3*x⁰
223ₓ = 2x²+2x+3
Substituting back into the equation, 2x²+2x+3 = 87
2x²+2x+3-87 = 0
2x²+2x-84 = 0
x²+x-42 = 0
On factorizing:
(x²+6x)-(7x-42) = 0
x(x+6)-7(x+6) = 0
(x+6)(x-7) = 0
x+6 = 0 and x-7 = 0
x = -6 and 7
<em>Hence the value of x is 7 (neglecting the negative value)</em>
Answer:
16-7x
Step-by-step explanation:
10x-3x+7-6-4x+5
16-7x
Answer:
Step-by-step explanation:
Given
--- domain
Required
Determine the range
To do this, we simply substitute the values of n in the given expression
So, we have:
Hence, the range is:
