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alexdok [17]3 years ago

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Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

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$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

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$AC=AB\sin 30^0\Rightarrow AC=6$ ft

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$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

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$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

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