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2 years ago

A preimage is the the original figure in a transformation. A) True B) False

2 answers:

7 0

Your answer is True! :) Reason: preimage is the original figure in transformation and preimage is the original figure in transformation.

scZoUnD [109]2 years ago

5 0

♥ A preimage is the the original figure in a transformation.A) True B) False
♥ A preimage is indeed the original figure in a transformation.

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Use exponents to write the numbers 81 and 64 in as many different ways as you can. Then write 64/81 using exponents in as many d

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Step-by-step explanation:

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2 years ago

You have a normal distribution of hours per week that music students practice. The mean of the values is 8 and the standard devi

Aleks04 [339]

Answer:

25%

Step-by-step explanation:

Since Normal Distribution is symmetrical Distribution and 5.3 and 10.7 are both 2.7 below and 2.7 above the mean respectively.

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2 years ago

2. List the like terms in each of the following i) 4x2 , -5x , 6 , 7x , -2x2 , -3

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1 year ago

Read 2 more answers

PLEASE HELP!!

lidiya [134]

Divide f(x) over g(x). To simplify, factor everything as much as possible and cancel out any common terms. In this case "4x+3" is a common term that shows up in the numerator and denominator.

(f/g)(x) = [ f(x) ]/[ g(x) ]
(f/g)(x) = (16x + 12)/(4x + 3)
(f/g)(x) = (4(4x+3))/(4x+3)
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So the answer is choice C

3 0

2 years ago

Solve the system: 2x+6y=36 x+4y=20

Assoli18 [71]

Let's solve this problem step-by-step

Let's set:

2x + 6y = 36 -- equation 1

x + 4y = 20 -- equation 2

(equation 2) * 2

2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

2y = 4

y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

x + 4(2) = 20

x = 20 - 8

x = 12

Thus x = 12 and y = 2

Let's check, by substituting these values

$2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20$

Answer: x = 12 and y = 2

Hope that helps!

5 0

2 years ago