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drek231 [11]
3 years ago
10

A preimage is the the original figure in a transformation. A) True B) False

Mathematics
2 answers:
Kitty [74]3 years ago
7 0
<span>Your answer is True! :) Reason: preimage is the original figure in transformation and </span><span>preimage is the original figure in transformation.</span>
scZoUnD [109]3 years ago
5 0
<span>♥ A preimage is the the original figure in a transformation.A) True B) False
</span>♥ A preimage is indeed the original figure in a transformation. 
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What is the simplified form of -(x-4)<br><br> -x-4<br> -x+4<br> X+4<br> X-4<br><br> Show your work
Sphinxa [80]

Answer:

Step-by-step explanation:

X-4

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2 years ago
Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ
mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant.  But maybe you don't know it isn't and it's a "trick" to throw you off.  Hmm...

Anyways, the half angle identity for tangent is

tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.  

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5.  That makes the missing side, by Pythagorean's Theorem, -3.  Filling in our formula:

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) } which simplifies a bit to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }  and a bit more to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }

Bring up the lower fraction and flip it to divide to get

tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1} which of course simplifies to

-3.  Choice A.

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Check the picture below.

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