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3 years ago

What is the absolute value of 5.23

1 answer:

3 0

Absolute Value is always positive, because it is the distance between any integer and zero. So, the absolute value of 5.23 is 5.23 (not negative)

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Please give 5 addition of polynomial examples

Dafna1 [17]

Answer:

Addition of Polynomials

1Add: 3x3 – 5x2 + 8x + 10, 15x3 – 6x – 23, 9x2 – 4x + 15 and -8x3 + 2x2 – 7x.

2Add: 7a + 5b, 6a – 6b + 3c and -5a + 7b + 4c. ...

3Add: 3a2 + ab – b2, -a2 + 2ab + 3b2 and 3a2 – 10ab + 4b2 ...

4Add: 5x + 3y, 4x – 4y + z and -3x + 5y + 2z. First we need to write in the addition form. ...

Step-by-step explanation:

Hope it helps ya ItzAlex

3 0

2 years ago

Which transformation is not isometric?

kumpel [21]

D .............................

7 0

3 years ago

Read 2 more answers

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago

Evaluate the expression \dfrac{x^5}{x^2} x 2 x 5 start fraction, x, start superscript, 5, end superscript, divided by, x, squa

Elza [17]

Answer:

Step-by-step explanation:

Fill in the variable value and do the arithmetic.

$\dfrac{2^5}{2^2}=\dfrac{32}{4}=8$

___

Of course, the fraction can be simplified first:

$\dfrac{x^5}{x^2}=x^{5-2}=x^3\\\\2^3=8$

7 0

2 years ago

X^2+y^2=25 find the distance of point (x,y) from origin

storchak [24]

Answer:

Step-by-step explanation:

The radius is 5.

All I do was think of the center-radius form a circle

(x-h)^2+(y-k)^2=r^2

x^2 + y^2 =25

(x-0)^2+(y-0)^2=5^2

The center is (0,0) and the radius is 5.

So a point on the circle (x,y) has a distance of 5 from the center

and the center's case here is (0,0).

3 0

2 years ago