Answer:
es 200
Step-by-step explanation:
100+100=200
0+0+0+0+0=0
Answer:
=x⁴−x³−14x²
Step-by-step explanation:
<h3>Let's simplify step-by-step.</h3>
x²(3x²+5x−4)−2x²(x²+3x+5)
<h3>Distribute:</h3>
=(x²)(3x²)+(x²)(5x)+(x²)(−4)+−2x⁴+−6x³+−10x²
=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²
<h3>Combine Like Terms:</h3>
=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²
=(3x⁴+−2x⁴)+(5x³+−6x³)+(−4x²+−10x²)
=x⁴+−x³+−14x²
<h3>ANS-</h3>
=x⁴−x³−14x²
7. x=3 is the midpoint between the roots. The other root is x = 2*3 -(-5) = 11.
8a) f(x) = (x +3)^2 -49. The vertex is (-3, -49). The roots are -10, 4.
8b) y = (x+4)^2 -1. The vertex is (-4, -1). The roots are -5, -3.
8c) f(x) = 2(x +3)^2 -34. The vertex is (-3, -34). The roots are -3±√17.
Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
