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2 years ago

Which represents a measure of volume? O 5 cm O 5 square cm 05 cm 05 cm

Mathematics

2 answers:

Elena-2011 [213]2 years ago

7 0

Answer:

a) 5 $cm^{3}$

Step-by-step explanation:

Bodies have three dimensions (width, height and depth). Measuring volume is calculating the number of cubic units that can fit inside.

When raising to 3, these dimensions are included and therefore 5 $cm^{3}$ is a measure of volume.

tester [92]2 years ago

7 0

Answer:

5cm^3

Step-by-step explanation:

Volume for a form will always be in cubic units.

Area of a shape will always be in squared units.

Length will not be in cubic or squared units.

Hence, the first option is a measure for volume.

The second option is equal to 5cm^2 which represents a measure for area, as does the fourth option.

The third option represents a measurement of length, for example the length of a line segment or the height of a figure.

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A triangle has an area of 38.4 cm2. The

lisov135 [29]

Answer:

6cm

Step-by-step explanation:

$A = \frac{h_b b}{2}$

$38.4 = \frac{12.8_b b}{2}$

$b = 2\frac{A}{h_b}$

$b = 2\frac{38.4}{12.8}$ = 6

8 0

2 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
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8 0

2 years ago

Read 2 more answers

UPS charges $8 flat fee and $0.20 for each pound. FedEx charges $3 flat fee and

Natasha_Volkova [10]

Answer:

50 lbs

Step-by-step explanation:

UPS: 8 + .20p

FedEx: 3 + .30p

8 + .20p = 3 + .30p

8 = 3 + .10p

5 = .10p

p = 50

4 0

2 years ago

Alg 2 please add explanation

irina [24]

Answer:

The answer is B

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

This problem I can’t seem to figure out

allochka39001 [22]

Answer:

39 touchdowns and 13 fieldgoals

Step-by-step explanation:

Let t= touchdowns

f = fieldgoals

They scored 35 times

t+f = 35

Touchdown is 7 pts and fieldgoal is 3 pt

7t+3f = 193

Multiply the first equation by-7

-7t -7f =-245

Add this to the second equation

-7t -7f =-245

7t+3f = 193

----------------------

-4f =-52

Divide by -4

-4f/-4 = -52/-4

f = 13

Now we can find t

t+f = 35

t+13 = 52

Subtract 13 from each side

t+13-13 =52-13

t =39

6 0

2 years ago