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gregori [183]
2 years ago
12

Find the perimeter of the polygon ABCD that has its vertices at A(2, –2), B(6, –2), C(6, 6), and D(2, 6).

Mathematics
1 answer:
sergiy2304 [10]2 years ago
7 0

Answer:

D. 24 Units

Step-by-step explanation:

tracing the points given we get a rectangle

the perimeter of a rectangle = 2a+2b

a=length

b= width

in this case a= 8

b= 4

the perimeter of a rectangle = (2*8)+(2*4)

the perimeter of a rectangle = 16+8

the perimeter of a rectangle = 24

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Answer:

b

Step-by-step explanation:

7 0
2 years ago
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A circle of radius of 4 inches has an arc length of 5.8 inches. Find the measure of the central angle.
kondor19780726 [428]
<h3>SOLUTION : </h3>

The radius of the circle is 4 inch and has an arc length of 5.8 inches . We know that if the central angle is 360° then the arc length is 2\pi r . Similarly when angle is theta ,

\implies Arc = radius \times \theta

Now substitute respective values , from the given data ,

\implies 5.8 inch = 4inch * \theta \\\\\implies 0.14 m = 0.1 * \theta \\\\\implies \boxed{\red{\theta \approx 1.4 \ rad }}

This is our required answer!

4 0
3 years ago
A horse walks around a circular track while its trainer stands in the center. The trainer is 14 feet from the horse at all times
max2010maxim [7]

The horse traveled 439.6 feet after walking around the track 5 times

<u><em>Solution:</em></u>

Given that, horse walks around a circular track while its trainer stands in the center

The trainer is 14 feet from the horse at all times

Therefore, radius of circular track = 14 feet

The circumference of circle is the distance traveled by horse for 1 lap

<em><u>The circumference of circle is given as:</u></em>

C = 2 \pi r

Where, "r" is the radius and \pi is a constant equal to 3.14

C = 2 \times 3.14 \times 14\\\\C = 87.92

Thus the distance traveled by horse for one time in circular track is 87.92 feet

<em><u>About how far had the horse traveled after walking around the track 5 times? </u></em>

Multiply the circumference by 5

distance = 5 \times 87.92\\\\distance = 439.6

Thus the horse traveled 439.6 feet after walking around the track 5 times

5 0
3 years ago
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Answer: Assuming that event A has occurred

Step-by-step explanation:

7 0
3 years ago
h = -16t^2 + 541? its been forever since i had to do this and frankly I'm completely lost. please if you answer this can you tea
natta225 [31]
A = -16  b = 0  c = 541
Use the quadratic formula which is
x = [-b +- sq root (b^2 -4*a*c)] / 2*a
x = [-0 +-sq root (0 -4*-16*541)] / 2 * -16
x = + - sq root (0 -4*-16*541) / -32
x = + - sq root (34,624) / -32
x = + - 186.075 / -32

x1 = 186.075 / -32 = <span> <span> <span> -5.81484375 </span> </span> </span>
x2 = -186.075 / -32 = <span> <span> <span> 5.81484375 </span> </span> </span>


7 0
3 years ago
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