Answer:
a=250
b=?
c=?
Step-by-step explanation:
b= what month, how many days
c=?
Answer: 45
Explanation:
The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement. Yes, there is a "relationship" regarding the tangent of the two acute angles (A and B) in a right triangle.
Recall that the perimeter is the sum of all the sides. So, for the first triangle, the perimeter is 4x+2+7x+7+5x-4 = 16x + 5
second triangle: x+3 + 2x-5 + x+7 (combine like terms)
Part b: Subtract the perimeter of the smaller triangle from the perimeter of the larger triangle.
J------------K------------L
8x+11 14x-1
<span>If K is the midpoint of JL then JK = KL
8x+11 = 14x-1
11 + 1 = 14x - 8x
12 = 6x
x = 12/6
x = 2
JK = 8x + 11 = 8*2 + 11 = 16+11 = 27
KL = JK = 27
JL = JK + KL = 27 + 27 = 54</span>
Answer: Option C.
Step-by-step explanation:
A) The result of the substitution shown in Option A is obtained by solving for y from the first equation and substituting into the second equation:
Therefore, this is a result of a substitution in the given system.
B) The result of the substitution shown in Option B is obtained by solving for y from the second equation and substituting into the first equation:
Therefore, this is a result of a substitution in the given system.
C) The result of the substitution shown in Option C is not a result of a substitution in the given system, because if you solve for x from the second equation and substitute into the first one, you get:
