The information given about the probability shows that the cardinality of D is 18.
<h3>How to calculate the probability?</h3>
From the complete information, the number of red-colored cards is 26.
Also, the number of red-colored number cards will be 18.
The cardinality of a set is a measure of a set's size, meaning the number of elements in the set.
Here, the cardinality of set D is 18.
Here is the complete question:
Take a deck of playing cards. Form following sets out of those:
A = Set of Face Cards
B = Set of Red Coloured Face cards
C = Set of Black Coloured Face Cards
D = Set of Red Coloured Number Cards
Find the Cardinality of set D
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Sin 45 = X / 14
X = 14 * sin45
X = 7√2≈9.89949
Thus ladder will reach to ≈ 9.9 (rouded-up) foot height in the building
<u>We are given:</u>
We know that the sum of all interior angles of a Pentagon is 540°
we are given 4 out of the 5 angles
<u>Solving for x:</u>
since the sum of all 5 angles is 540°:
75 + 130 + 135 + x + 90 = 540
x + 430 = 540
x = 540 - 430
x = 110°
A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.
There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.
The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.
However, if the question were to say "and," we would multiply the two probabilities.
Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).
Now we can add them together.
This cannot be simplified further, so the probability is 17 in 52, or 33%.
hope this helps!
Answer: a = 1/6
Explanation: Convert the mixed number into an improper fractions. Which is 21/4.
Then you can do the butterfly method.
