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Anna71 [15]
3 years ago
15

1) If the parent function is f(x)=\xl, which transformation would shift the

Mathematics
1 answer:
gayaneshka [121]3 years ago
4 0

Answer:

The last one.

Step-by-step explanation:

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The sum of two numbers is 58. The smaller number is 20 less than the larger number. What are the numbers?
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A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul
pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

\hat p = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion  is given by;

     P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.6858

           n = sample of respondents = 2,610

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at

                                   2.5% level of significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }]

  = [ 0.6858-1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } , 0.6858+1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} } ]

  = [0.668 , 0.704]

Therefore, 95% confidence interval for the population proportion of the adults is (0.668, 0.704).

3 0
3 years ago
I need help ASAP! Find the area of the following shape.
ValentinkaMS [17]
Hey i can’t see the picture, it’s too pixelated and like has lines all over it, maybe post it again if love to help :)
8 0
3 years ago
Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2
zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

Step-by-step explanation:

Un par ordenado es un elemento de la forma (x,f(x)), donde x es un elemento del dominio de la función, mientras f(x) es la imagen de la función evaluada en x. Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

x \rightarrow f(x)

Dado que f(x) es una función polinómica, existe una imagen para todo elemento x. Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

f(0) = 0^{3}-2\cdot (0)^{2}-2

f(0) = -2

(0, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 1

f(1) = 1^{3}-2\cdot (1)^{2}-2

f(1) = -3

(1, -3) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 2

f(2) = 2^{3}-2\cdot (2)^{2}-2

f(2) = -2

(2, -2) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

x = 3

f(3) = 3^{3}-2\cdot (3)^{2}-2

f(3) = 7

(3, 7) es un par ordenado de f(x) = x^{3}-2\cdot x^{2}-2.

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de f(x) = x^{3}-2\cdot x^{2}-2.

6 0
3 years ago
Can someone pleaseeeeee help on either question pleaseeeee 100000000 points
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Number 3 is gonna be 2 and Number 4 will be 294 I hope this would help u a little bit I will figure out the Other questions



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3 years ago
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