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LekaFEV [45]
2 years ago
15

if the gcf of two numbers is 1, they are called relatively prime. find 3 sets of relatively prime numbers

Mathematics
1 answer:
Alex Ar [27]2 years ago
7 0
What school do you go to cause I
think I know you
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Which undefined term can contain parallel lines?
White raven [17]
Coplanor lines that never intersect 
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3 years ago
Please help!!!!!!!!!!!!!
Yuri [45]

Answer:

37, 3, 37

Step-by-step explanation:

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If in one year a city recorded a total of 97 rainy, how many of the days did it not rain?
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1 year = 365 days

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3 years ago
5^2•3^-1•5^-3/3^4•5^-1•3^-3
puteri [66]
Assuming you want the expression to be simplified. 

We begin with the following: 

5^{2} * 3^{-1} * \frac{5^-3}{3^{4}} * 5^{-1} * 3^{-3}

Simplify the first part, 5^{2}. That is 25. Now we have this: 

25*3^{-1.5} * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3} 

Next, simplify 3^{-1}, which is 1/3, and get this: 

25* 1/3 * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3} 

The next part is \frac{5^-3}{3^{4}}. Simplify the denominator, 3^{4}, which is 81. Simplify the numerator, which is 1/125. Then divide 1/125 by 81, which we will keep as a fraction for simplicity's sake, but simplify it to \frac{1}{10125}. Now we have: 

25* 1/3 * \frac{1}{10125} * 5^{-1} * 3^{-3}

Now simplify 5^{-1}, which is 0.2, or 1/5. Now we have: 

25* 1/3 * \frac{1}{10125} * 0.2 * 3^{-3} 

Finally, simplify 3^{-3}. That is 1/27. We have: 

25* 1/3 * \frac{1}{10125} * 0.2 * 1/27

Lastly, multiply them all together! Now we are done, with the product of: 

\frac{1}{6075}

That certainly did take a while to type in all the LaTex, so I really hope that helped!

Note- if anything isn't working with the LaTex, just tell me and I'll fix it! (:
3 0
2 years ago
Find the number that makes the ration equivalent to 77:99
Leno4ka [110]
Each are divisible by 11 so the ratio equivalent would be 7:9
7 0
3 years ago
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