All categories

3 years ago

Where are all the lines of symmetry in a square?

Mathematics

1 answer:

mart [117]3 years ago

6 0

First straight in the middle second diagonal

You might be interested in

Please help me with this question!!!!

elixir [45]

Answer:

We know the are of the square is 7x as that squared would =49x^2 making the perimeter 28x so the last side of the triangle has to be 21x-4

5 0

3 years ago

HELPPPPPPPPP CAP ARE ON BUT HELPPPPPPPP MEH PLS

aleksandr82 [10.1K]

Answer: The picture blury

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A submarine dove to a point 1760 feet below sea level.

Ivahew [28]

-1760. Just let 0 be sea level

7 0

3 years ago

Read 2 more answers

Find the side in of point a to point c

vladimir1956 [14]

Step 1:

Calculate the measure of angle ∠ABC

$\angle DBC+\angle ABC=180(\text{ sum of angles on a straight line)}$ $\angle ABC=65^0$ $\begin{gathered} \angle DBC+\angle ABC=180 \\ \angle DBC+65^0=180^0 \\ \angle DBC=180^0-65^0 \\ \angle DBC=115^0 \end{gathered}$

From the triangle in the question,

$a=10\operatorname{km},c=15\operatorname{km},B=115^0$

Step 2:

Calculate the value of AB using the cosine rule below

$b^2=a^2+c^2-2\times a\times c\times\cos B$

By substituting the values, we will have

$\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}$

Hence,

The distance of point A to point C is = 21.26km

3 0

1 year ago

HELP ITS TIMED PLEASE IM BEGGING YOU

Blababa [14]

The answer is letter A and letter D

5 0

3 years ago