615 - 6 = 609
963 - 6 = 957
609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.
Answer:
tan teeta = <u>oppos</u><u>ite</u>
adjacent
45°= <u>7</u>
x
multiply both sides by x
which will now give us
<u>45°x</u>=<u>7</u>
45°. 45°
x= 0.16
hope it helps
