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3 years ago

Please help

Mathematics

1 answer:

murzikaleks [220]3 years ago

6 0

Answer:

$74.41

Step-by-step explanation:

x = Amount of money Sylvia had in her account

Amount of money spent at the Grocery Store= $25.89

Remaining Amount of money after Grocery = $48.52

Hence, By adding the two amount above we get the amount Sylvia had in her account before grocery;

x = $25.89 + $48.52

x = $74.41

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Leona [35]

Let's say we wanted to subtract these measurements.

We can do the calculation exactly:

45.367 - 43.43 = 1.937

But let's take the idea that measurements were rounded to that last decimal place.

So 45.367 might be as small as 45.3665 or as large as 45.3675.

Similarly 43.43 might be as small as 43.425 or as large as 43.435.

So our difference may be as large as

45.3675 - 43.425 = 1.9425

or as small as

45.3665 - 43.435 = 1.9315

If we express our answer as 1.937 that means we're saying the true measurement is between 1.9365 and 1.9375. Since we determined our true measurement was between 1.9313 and 1.9425, the measurement with more digits overestimates the accuracy.

The usual rule is to when we add or subtract to express the result to the accuracy our least accurate measurement, here two decimal places.

We get 1.94 so an imputed range between 1.935 and 1.945. Our actual range doesn't exactly line up with this, so we're only approximating the error, but the approximate inaccuracy is maintained.

7 0

3 years ago

Read 2 more answers

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are

Kruka [31]

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of type A paint

x2 = sample mean of type B paint

s1 = sample standard deviation type A paint

s2 = sample standard for type B paint

n1 = number of samples of type A paint

n2 = number of samples of type B paint

From the information given,

x1 = 75.7

s1 = 4.5

n1 = 11

x2 = 64.3

s2 = 5.1

n2 = 9

x1 - x2 = 75.7 - 64.3 = 11.4

√(s1²/n1 + s2²/n2) = √(4.5²/11 + 5.1²/9) = √4.709

Degree of freedom = (n1 - 1) + (n2 - 1)

df = (11 - 1) + (9 - 1) = 18

For the 98% confidence interval, the z score from the t distribution table is 2.552

Margin of error = 2.552√4.709 = 5.55

The upper boundary for the confidence interval is

11.4 + 5.55 = 16.95 hours

The lower boundary for the confidence interval is

11.4 - 5.55 = 5.85 hours

The correct option is

B. 5.85 hrs < μ1 - μ2 < 16.95 hrs

4 0

3 years ago

A committee has thirteen members. There are three members that currently serve as the board's chairman, ranking member, and tre

kogti [31]

Answer: Probability P = 1/1716

Step-by-step explanation:

Definition

For permutation ( order is important)

nPr = n!/(n-r)!

Given;

Total number of members in the committee = 13

Total number of members to be selected = 3

Since order is important in this case.

The total number (Tt) of possible ways of selecting three executives from the committee members is given as

Tt = 13P3 (since order is important)

Tt = 13!/(13-3)!

Tt = 13!/10!

Tt = 1716

The probability P of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions is equal to

P = number of favourable outcomes/ number of possible outcomes

Number of favourable outcomes = 1 (i.e 1×1×1 = 1) one option for each post.

Number of possible outcomes = Tt = 1716

P = 1/1716

7 0

3 years ago

Attached as picture. Please read fully

Troyanec [42]

a. The velocity t = $v = Ce_{n} (\frac{mo}{mo - kt} ) - gt$

b. v60 = 7164

<h3>How to solve for the velocity</h3>

mdv/dt = ck - mg

dv/dt = ck/m - mg/m

= ck/m - g

dv = $(\frac{ck}{Mo-Kt} -g)dv$

Integrate the two sides of the equation to get

v $-\frac{ck}{k} e_{n} (Mo- kt)-gt+c$

$v = Ce_{n} (\frac{mo}{mo - kt} ) - gt$

b. fuel accounts for 55% of the mass

So final mass after fuel is burned out is = 0.45

c=2500

g=9.8

t=60

v = -2500ln0.45 - 9.8 x 60

= 7752 - 588

= 7164

<h3>Complete question</h3>

A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.

dv dt m =ck - mg

(a) Find v(t) keeping in mind that the mass m is a function of t.

v(t) =

m/sec

(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]

v(60) =

m/sec [Round to nearest whole number]

Raed more on velocity here

brainly.com/question/25749514

#SPJ1

8 0

2 years ago

Edward invested $1600 in a savings account for 8 years. At the end of 8 years, his savings account had $1920 in it.

miss Akunina [59]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$1920\\
P=\textit{original amount deposited}\to& \$1600\\
r=rate\to r\%\to \frac{r}{100}\\
t=years\to &8
\end{cases}
\\\\\\
1920=1600(1+r8)\implies \cfrac{1920}{1600}=1+8r\implies \cfrac{6}{5}=1+8r
\\\\\\
\cfrac{6}{5}-1=8r\implies \cfrac{\frac{6}{5}-1}{8}=r\implies \cfrac{\frac{1}{5}}{8}=r\implies \cfrac{1}{40}=r
\\\\\\
0.025=r\implies r\%=100\cdot 0.025\implies r=\stackrel{\%}{2.5}$

8 0

3 years ago