Answer:
the student should score atleast 229 to be among the top 10%.
Step-by-step explanation:
in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)

after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.
we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)
looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)




the student should score atleast 229 to be among the top 10%.
Answer:

And solving we got:



Step-by-step explanation:
For this case we can define the following notation:
represent the width
And we want a maximum error of 0.0003 so we can set up the following equation:

And solving we got:



The graph of an absolute value parent function is a pair of rays in quadrant 1 & 2, as shown in the graph.
The absolute value function is
f(x) = |x| or y = |x|
We also know that the absolute function can be wriiten as
y = |x|
=> y = x or y = -x
Comparing with y = mx + c
We get
m = 1 or m=-1 and c = 0
c = 0 implies that the line passes through the origin.
Hence the slopes shall be -1, 1 & the line passes through the origin.
Option A, B & D are the right answers.
Answer:
Step-by-step explanation:
So, to start, we need to label all the values. This is
16, 17, 17, 17, 18, 18 , 18 , 18, 18, 18, 19, 19, and 20.
The Lower Quartile can be found if you know the median. The median in this case is 18. So, the Lower Quartile is just median between the median and the lowest number. So it is the median between 18 and 16. Not average, but the median in the set. In this case it is 17. The Upper Quartile is the same except now it is between the median and highest value, or 18.5. The IQR is found by subtracting the Upper by the Lower, or 18.5-17, or 1.5.
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