Let two number A and B, and A >B
as we know A+10=2B① && A+B =38②
①-② solve that
B=16 so A=22
so, they are 16 and 22
1. X + 5
2.15-15
3. C= ( 3x9.95)+(2x14.98)
4.?
5. 12,000+500x ?idk
Answer:
No entiendo
Step-by-step explanation:
Find the area of the rectangle. You can find the area of a rectangle with the following formula:

w = width, and l = length.
Plug in your width and length:

The area of the rectangle is 200 square centimeters.
The area of a square is also given by width * length. Multiply the sides together:

The area of a square is 4x^2.
Because you're cutting away the square from the rectangle, you will subtract the area of the square from the area of the rectangle. The following equation will be your answer:
In a Rhombus the diagonals intersect and divides it in two equal halves.
Therefore LP = 28/2
LP = 14cm
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