Josiah invests $360 into an account that accrues 3% interest annually. Assuming no deposits or withdrawals are made, which equat
2 answers:
Answer:
y = 360(1.03)x
Step-by-step explanation:
F is the future worth, P is the present worth, I will be the interest rate, and n is the number of years.
The principal amount of the money = $360
Annual rate of interest = 3%
Thus, the amount after x years which is increased by 3%.
Since, this amount represented by y,
The required equation that represents the amount of money in Josiah’s account, y, after x years is,
This amount represented by y,
Therefore, the required equation that represents the amount of money in Josiah’s account, y, after x years is,
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9×10⁴ is 300 times greater than 3×10²
as, (9×10⁴)/(3×10²)=3× 10²
and the proper of writting powers in computer form is a×10^b
as, (9×10⁴)/(3×10²)=3× 10²
and the proper of writting powers in computer form is a×10^b
9514 1404 393
Answer:
20
Step-by-step explanation:
As with any evaluation problem, take it step by step according to the order of operations.
The first thing you need to do here is compute a#b.
The given definition can be simplified a bit for evaluation purposes:
a#b = a²b -ab² = ab(a -b)
Then for a=3 and b=-2, you have ...
(3)#(-2) = (3)(-2)(3 -(-2)) = -6(5) = -30
Now, you are in a position to evaluate the expression you're asked for.
